Minggu, 07 Juni 2015

quiz

Quiz Soal QUIZ Suatu kelurahan mendapatkan Bantuan Langsung Tunai dari pemerintah untuk masing masing kepala keluarga dengan syarat ketentuan sebagai berikut : C1 : Jumlah Tanggungan C2 : Pendapatan Kepala Keluarga C3 : Luas Bangunan Rumah C4 : Memiliki KK Pilihlah 5 alternatif KK yang akan mendapatkan bantuan dari beberapa KK berikut ini :
 NKK C1 C2 C3 C4
Aldyan 4 2.350.000 100M² Tidak ada
Hendro 5 3.050.000 50M² Ada Joko 3 3.350.000 70M² Ada
Doni 4 2.550.000 90M² Ada
Dono 6 2.850.000 120M² Ada Kasino 3 2.650.000 80M² Ada
Susanto 2 3.350.000 150M² Tidak ada
Bobot W = [5,4,3,4] NKK C1 C2 C3 C4
 Aldyan 2 1 3 1 Hendro 3 3 1 2 Joko 2 4 1 2 Doni 2 2 2 2 Dono 3 3 4 2 Bobot W= [5,4,3,4] Penyelesaian 1.X1 = √2²+3²+2²+2²+2² = 5.4772 r11= 2/5.4772 =0.3651 r41= 2/5.4772 =0.3651 r21= 3/5.4772 =0.5477 r51= 3/5.4772 =0.5477 r31= 2/5.4772 =0.3651 X2 =√1²+3²+4²+2²+3² = 6.7823 r12= 2/6.7823 =0.1474 r41= 2/6.7823 =0.2948 r22= 3/6.7823 =0.4423 r51= 3/6.7823 =0.423 r32= 4/6.7823 =0.5897 X3 =√3²+1²+1²+2²+4² = 5.5677 r13= 3/5.5677 =0.5388 r43= 2/5.5677 =0.3592 r23= 1/5.5677 =0.1786 r53= 4/5.5677 =0.7184 r33= 1/5.5677 =0.1786 X4=√1²+2²+2²+2²+2² = 4.1231 r14= 1/4.1231 =0.2425 r44= 2/4.1231 =0.4850 r24= 2/4.1231 =0.4850 r45= 2/4.1231 =0.4850 r34= 2/4.1231 =0.4850 0.3651 0.1474 0.5388 0.2425 0.5477 0.4423 0.1796 0.4850 Matrik R 0.3651 0.5897 0.1796 0.4850 0.3651 0.2984 0.3592 0.4850 0.5477 0.4423 0.7184 04850 2. y11=w1 r11= 5*0.3651 = 1.8255 y21=w1 r21= 5*0.5477 = 2.7385 y31=w1 r31= 5*0.3651 = 1.8255 y41=w1 r41= 5*0.3651 = 1.8255 y51=w1 r51= 5*0.5477 = 2.7385 y12=w2 r12= 4*0.1474 = 0.5896 y22=w2 r22= 4*0.4423 = 1.7692 y32=w2 r32= 4*0.5877 = 2.3588 y42=w2 r42= 4*0.2984 = 1.1936 y52=w2 r52= 4*0.4423 = 1.7692 y13=w3r13 = 3*0.5388 = 1.6164 y23=w3r23 = 3*0.1796 = 0.5388 y33=w3r33 = 3*0.1796 = 0.5388 y43 =w3r43 = 3*0.3592 = 1.0776 y53 = w3r53 = 3*0.7184 = 2.1552 y14 = w4r14 = 4*0.2425 = 0.97 y24 = w4r24 = 4*0.4850 = 1.94 y34 = w4r34 = 4*0.4850 = 1.94 y44 = w4r44 = 4*0.4850 = 1.94 y54 = w4r54 = 4*0.4850 = 1.94 1.8255 0.5896 1.6164 0.97 2.7385 1.7692 0.5388 1.94 Matrik y 1.8225 2.3588 0.5388 1.94 1.8255 1.1936 1.0776 1.94 2.7385 1.7692 2.1552 1.94 3. y1⁺ = max {1.8255 ; 2.7385 ; 1.8255 ; 1.8255 ; 2.7385} = 2.7385 y2 ̄ = min {0.5896 ; 1.7692 ; 2.3588 ; 1.1936 ; 1.7692} = 0.5896 y3 ̄ = min {1.6164 ; 0.5388 ; 0.5388 ; 1.0776 ; 2.1552} = 0.5388 y4⁺ = max {0.97 ; 1.94 ; 1.94 ; 1.94 ; 1.94} = 1.94 A⁺ ={ 2.7385 ; 0.5896 ; 0.5388 ; 1.94 } y1 ̄ = min {1.8255 ; 2.7385 ;1.8255 ; 1.82556 ; 2.7385} = 1.8255 y2⁺ = max {0.5896 ; 1.7692 ; 2.3588 ; 1.1936 ; 1.7692} = 2.3588 y3 ⁺= max {1.6164 ; 0.5388 ; 0.5388 ; 1.0776 ; 2.1552} = 2.1552 y4 ̄ = max {0.97 ; 1.94 ; 1.94 ; 1.94 ; 1.94} = 0.97 A ̄ ={ 1,8255 ; 2.3588 ; 2.1552; 0.97} 4. D1⁺= √(1.8225 - 2.7385)²+(0.5896 – 0.5896)² + (1.6164 – 0.5388)²+ (0.97 - 1.94)² = 1.7149 D2 ̄ = √(2.7385 - 2.7385)²+(1.7672 – 0.5896)² + (0.5388 – 0.5388)²+ (1.94- 1.94)² = 1.1796 D3 ̄ = √(1.8255 - 2.7385)²+(2.3588 – 0.5896)² + (0.5388 – 0.5388)²+ (1.94- 1.94)² = 1.9908 D4⁺= √(2.7385- 2.7385)²+(1.7692 – 0.5896)² + (2.1552 – 0.5388)²+ (1.94 - 1.94)² = 2.0010 D1 ̄= √(1.8225 – 1.8225)²+(0.5896 – 2.3588)² + (1.6164 – 2.1552)²+ (0.97 – 0.97)² = 1.8494 D2⁺ = √(2.7385 – 1.8225)²+(1.7672 – 2.3588)² + (0.5388 – 2.1552)²+ (1.94- 0.97)² = 2.1772 D3⁺= √(1.8255 – 1.8225)²+(2.3588 – 2.3588)² + (0.5388 – 2.1552)²+ (1.94- 0.97)² = 1.8850 D4 ̄= √(2.7385- 1.8225)²+(1.7692 – 2.3588)² + (2.1552 – 2.1552)²+ (1.94 – 0.97)² = 1.4585 5. V1 = 1.8479/1.9479+1.7149 = 0.5186 V2 = 2.1772/2.1172+1.1796 = 0.6485 V3 = 1.8850/1.8850+1.9908 = 0.4863 V4 = 1.4585/1.4585+2.0010 = 0.4215